Ten > Quadratic Equation
x^2 - 45x + 324 = 0 | Solve by factorization method.
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Solution
The required values of x are x = {9, 36}.
Given
$\rm x^{2} - 45 x + 324 = 0$
$\rm or, x^{2} - (36 + 9) x + 324 = 0$
$\rm or, x^{2} - 36 x- 9x + 324 = 0$
$\rm or, x (x - 36) - 9 (x - 36) = 0$
$\rm or, (x - 9)(x - 36) = 0$
Either
$\rm (x - 9) = 0$
$\rm \therefore x = 9$
Or
$\rm (x - 36) = 0$
$\rm \therefore x = 36$
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